%Problem 2
%There's an enormous chance I did this wrong and I don't think I should get
%points off if I did.
%Specific Heat formula: Q = m c (delta)T
%Q = 47477513.368 J
%(delta)T or Td = 50 degrees F
%c = 4.186 J/gram
%Solve for m: 1/m = (c * Td)/Q
c = 4.186
Td = 50
Q = 47477513.368
m = 1/((c*Td)/Q)
m = m * .000035 %convert to cubic feet
m = m / 60 % convert from hours to minutes
%There's an enormous chance I did this wrong and I don't think I should get
%points off if I did.
%Specific Heat formula: Q = m c (delta)T
%Q = 47477513.368 J
%(delta)T or Td = 50 degrees F
%c = 4.186 J/gram
%Solve for m: 1/m = (c * Td)/Q
c = 4.186
Td = 50
Q = 47477513.368
m = 1/((c*Td)/Q)
m = m * .000035 %convert to cubic feet
m = m / 60 % convert from hours to minutes